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diff --git a/qa/rpc-tests/replace-by-fee.py b/qa/rpc-tests/replace-by-fee.py
index 537a1ed8d9..6e9e0b304c 100755
--- a/qa/rpc-tests/replace-by-fee.py
+++ b/qa/rpc-tests/replace-by-fee.py
@@ -1,512 +1,517 @@
#!/usr/bin/env python2
# Copyright (c) 2014-2015 The Bitcoin Core developers
# Distributed under the MIT software license, see the accompanying
# file COPYING or http://www.opensource.org/licenses/mit-license.php.
#
# Test replace by fee code
#
from test_framework.test_framework import BitcoinTestFramework
from test_framework.util import *
from test_framework.script import *
from test_framework.mininode import *
import binascii
COIN = 100000000
MAX_REPLACEMENT_LIMIT = 100
def satoshi_round(amount):
return Decimal(amount).quantize(Decimal('0.00000001'), rounding=ROUND_DOWN)
def txToHex(tx):
return binascii.hexlify(tx.serialize()).decode('utf-8')
def make_utxo(node, amount, confirmed=True, scriptPubKey=CScript([1])):
"""Create a txout with a given amount and scriptPubKey
Mines coins as needed.
confirmed - txouts created will be confirmed in the blockchain;
unconfirmed otherwise.
"""
fee = 1*COIN
while node.getbalance() < satoshi_round((amount + fee)/COIN):
node.generate(100)
#print (node.getbalance(), amount, fee)
new_addr = node.getnewaddress()
#print new_addr
txid = node.sendtoaddress(new_addr, satoshi_round((amount+fee)/COIN))
tx1 = node.getrawtransaction(txid, 1)
txid = int(txid, 16)
i = None
for i, txout in enumerate(tx1['vout']):
#print i, txout['scriptPubKey']['addresses']
if txout['scriptPubKey']['addresses'] == [new_addr]:
#print i
break
assert i is not None
tx2 = CTransaction()
tx2.vin = [CTxIn(COutPoint(txid, i))]
tx2.vout = [CTxOut(amount, scriptPubKey)]
tx2.rehash()
tx2_hex = binascii.hexlify(tx2.serialize()).decode('utf-8')
#print tx2_hex
signed_tx = node.signrawtransaction(binascii.hexlify(tx2.serialize()).decode('utf-8'))
txid = node.sendrawtransaction(signed_tx['hex'], True)
# If requested, ensure txouts are confirmed.
if confirmed:
while len(node.getrawmempool()):
node.generate(1)
return COutPoint(int(txid, 16), 0)
class ReplaceByFeeTest(BitcoinTestFramework):
def setup_network(self):
self.nodes = []
self.nodes.append(start_node(0, self.options.tmpdir, ["-maxorphantx=1000",
- "-relaypriority=0", "-whitelist=127.0.0.1"]))
+ "-relaypriority=0", "-whitelist=127.0.0.1",
+ "-limitancestorcount=50",
+ "-limitancestorsize=101",
+ "-limitdescendantcount=200",
+ "-limitdescendantsize=101"
+ ]))
self.is_network_split = False
def run_test(self):
make_utxo(self.nodes[0], 1*COIN)
print "Running test simple doublespend..."
self.test_simple_doublespend()
print "Running test doublespend chain..."
self.test_doublespend_chain()
print "Running test doublespend tree..."
self.test_doublespend_tree()
print "Running test replacement feeperkb..."
self.test_replacement_feeperkb()
print "Running test spends of conflicting outputs..."
self.test_spends_of_conflicting_outputs()
print "Running test new unconfirmed inputs..."
self.test_new_unconfirmed_inputs()
print "Running test too many replacements..."
self.test_too_many_replacements()
print "Running test opt-in..."
self.test_opt_in()
print "Passed\n"
def test_simple_doublespend(self):
"""Simple doublespend"""
tx0_outpoint = make_utxo(self.nodes[0], 1.1*COIN)
tx1a = CTransaction()
tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)]
tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))]
tx1a_hex = txToHex(tx1a)
tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
# Should fail because we haven't changed the fee
tx1b = CTransaction()
tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
tx1b.vout = [CTxOut(1*COIN, CScript([b'b']))]
tx1b_hex = txToHex(tx1b)
try:
tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
except JSONRPCException as exp:
assert_equal(exp.error['code'], -26) # insufficient fee
else:
assert(False)
# Extra 0.1 BTC fee
tx1b = CTransaction()
tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
tx1b.vout = [CTxOut(0.9*COIN, CScript([b'b']))]
tx1b_hex = txToHex(tx1b)
tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
mempool = self.nodes[0].getrawmempool()
assert (tx1a_txid not in mempool)
assert (tx1b_txid in mempool)
assert_equal(tx1b_hex, self.nodes[0].getrawtransaction(tx1b_txid))
def test_doublespend_chain(self):
"""Doublespend of a long chain"""
initial_nValue = 50*COIN
tx0_outpoint = make_utxo(self.nodes[0], initial_nValue)
prevout = tx0_outpoint
remaining_value = initial_nValue
chain_txids = []
while remaining_value > 10*COIN:
remaining_value -= 1*COIN
tx = CTransaction()
tx.vin = [CTxIn(prevout, nSequence=0)]
tx.vout = [CTxOut(remaining_value, CScript([1]))]
tx_hex = txToHex(tx)
txid = self.nodes[0].sendrawtransaction(tx_hex, True)
chain_txids.append(txid)
prevout = COutPoint(int(txid, 16), 0)
# Whether the double-spend is allowed is evaluated by including all
# child fees - 40 BTC - so this attempt is rejected.
dbl_tx = CTransaction()
dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
dbl_tx.vout = [CTxOut(initial_nValue - 30*COIN, CScript([1]))]
dbl_tx_hex = txToHex(dbl_tx)
try:
self.nodes[0].sendrawtransaction(dbl_tx_hex, True)
except JSONRPCException as exp:
assert_equal(exp.error['code'], -26) # insufficient fee
else:
assert(False) # transaction mistakenly accepted!
# Accepted with sufficient fee
dbl_tx = CTransaction()
dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
dbl_tx.vout = [CTxOut(1*COIN, CScript([1]))]
dbl_tx_hex = txToHex(dbl_tx)
self.nodes[0].sendrawtransaction(dbl_tx_hex, True)
mempool = self.nodes[0].getrawmempool()
for doublespent_txid in chain_txids:
assert(doublespent_txid not in mempool)
def test_doublespend_tree(self):
"""Doublespend of a big tree of transactions"""
initial_nValue = 50*COIN
tx0_outpoint = make_utxo(self.nodes[0], initial_nValue)
def branch(prevout, initial_value, max_txs, tree_width=5, fee=0.0001*COIN, _total_txs=None):
if _total_txs is None:
_total_txs = [0]
if _total_txs[0] >= max_txs:
return
txout_value = (initial_value - fee) // tree_width
if txout_value < fee:
return
vout = [CTxOut(txout_value, CScript([i+1]))
for i in range(tree_width)]
tx = CTransaction()
tx.vin = [CTxIn(prevout, nSequence=0)]
tx.vout = vout
tx_hex = txToHex(tx)
assert(len(tx.serialize()) < 100000)
txid = self.nodes[0].sendrawtransaction(tx_hex, True)
yield tx
_total_txs[0] += 1
txid = int(txid, 16)
for i, txout in enumerate(tx.vout):
for x in branch(COutPoint(txid, i), txout_value,
max_txs,
tree_width=tree_width, fee=fee,
_total_txs=_total_txs):
yield x
fee = 0.0001*COIN
n = MAX_REPLACEMENT_LIMIT
tree_txs = list(branch(tx0_outpoint, initial_nValue, n, fee=fee))
assert_equal(len(tree_txs), n)
# Attempt double-spend, will fail because too little fee paid
dbl_tx = CTransaction()
dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
dbl_tx.vout = [CTxOut(initial_nValue - fee*n, CScript([1]))]
dbl_tx_hex = txToHex(dbl_tx)
try:
self.nodes[0].sendrawtransaction(dbl_tx_hex, True)
except JSONRPCException as exp:
assert_equal(exp.error['code'], -26) # insufficient fee
else:
assert(False)
# 1 BTC fee is enough
dbl_tx = CTransaction()
dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
dbl_tx.vout = [CTxOut(initial_nValue - fee*n - 1*COIN, CScript([1]))]
dbl_tx_hex = txToHex(dbl_tx)
self.nodes[0].sendrawtransaction(dbl_tx_hex, True)
mempool = self.nodes[0].getrawmempool()
for tx in tree_txs:
tx.rehash()
assert (tx.hash not in mempool)
# Try again, but with more total transactions than the "max txs
# double-spent at once" anti-DoS limit.
for n in (MAX_REPLACEMENT_LIMIT+1, MAX_REPLACEMENT_LIMIT*2):
fee = 0.0001*COIN
tx0_outpoint = make_utxo(self.nodes[0], initial_nValue)
tree_txs = list(branch(tx0_outpoint, initial_nValue, n, fee=fee))
assert_equal(len(tree_txs), n)
dbl_tx = CTransaction()
dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
dbl_tx.vout = [CTxOut(initial_nValue - 2*fee*n, CScript([1]))]
dbl_tx_hex = txToHex(dbl_tx)
try:
self.nodes[0].sendrawtransaction(dbl_tx_hex, True)
except JSONRPCException as exp:
assert_equal(exp.error['code'], -26)
assert_equal("too many potential replacements" in exp.error['message'], True)
else:
assert(False)
for tx in tree_txs:
tx.rehash()
self.nodes[0].getrawtransaction(tx.hash)
def test_replacement_feeperkb(self):
"""Replacement requires fee-per-KB to be higher"""
tx0_outpoint = make_utxo(self.nodes[0], 1.1*COIN)
tx1a = CTransaction()
tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)]
tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))]
tx1a_hex = txToHex(tx1a)
tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
# Higher fee, but the fee per KB is much lower, so the replacement is
# rejected.
tx1b = CTransaction()
tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
tx1b.vout = [CTxOut(0.001*COIN, CScript([b'a'*999000]))]
tx1b_hex = txToHex(tx1b)
try:
tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
except JSONRPCException as exp:
assert_equal(exp.error['code'], -26) # insufficient fee
else:
assert(False)
def test_spends_of_conflicting_outputs(self):
"""Replacements that spend conflicting tx outputs are rejected"""
utxo1 = make_utxo(self.nodes[0], 1.2*COIN)
utxo2 = make_utxo(self.nodes[0], 3.0*COIN)
tx1a = CTransaction()
tx1a.vin = [CTxIn(utxo1, nSequence=0)]
tx1a.vout = [CTxOut(1.1*COIN, CScript([b'a']))]
tx1a_hex = txToHex(tx1a)
tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
tx1a_txid = int(tx1a_txid, 16)
# Direct spend an output of the transaction we're replacing.
tx2 = CTransaction()
tx2.vin = [CTxIn(utxo1, nSequence=0), CTxIn(utxo2, nSequence=0)]
tx2.vin.append(CTxIn(COutPoint(tx1a_txid, 0), nSequence=0))
tx2.vout = tx1a.vout
tx2_hex = txToHex(tx2)
try:
tx2_txid = self.nodes[0].sendrawtransaction(tx2_hex, True)
except JSONRPCException as exp:
assert_equal(exp.error['code'], -26)
else:
assert(False)
# Spend tx1a's output to test the indirect case.
tx1b = CTransaction()
tx1b.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0)]
tx1b.vout = [CTxOut(1.0*COIN, CScript([b'a']))]
tx1b_hex = txToHex(tx1b)
tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
tx1b_txid = int(tx1b_txid, 16)
tx2 = CTransaction()
tx2.vin = [CTxIn(utxo1, nSequence=0), CTxIn(utxo2, nSequence=0),
CTxIn(COutPoint(tx1b_txid, 0))]
tx2.vout = tx1a.vout
tx2_hex = txToHex(tx2)
try:
tx2_txid = self.nodes[0].sendrawtransaction(tx2_hex, True)
except JSONRPCException as exp:
assert_equal(exp.error['code'], -26)
else:
assert(False)
def test_new_unconfirmed_inputs(self):
"""Replacements that add new unconfirmed inputs are rejected"""
confirmed_utxo = make_utxo(self.nodes[0], 1.1*COIN)
unconfirmed_utxo = make_utxo(self.nodes[0], 0.1*COIN, False)
tx1 = CTransaction()
tx1.vin = [CTxIn(confirmed_utxo)]
tx1.vout = [CTxOut(1.0*COIN, CScript([b'a']))]
tx1_hex = txToHex(tx1)
tx1_txid = self.nodes[0].sendrawtransaction(tx1_hex, True)
tx2 = CTransaction()
tx2.vin = [CTxIn(confirmed_utxo), CTxIn(unconfirmed_utxo)]
tx2.vout = tx1.vout
tx2_hex = txToHex(tx2)
try:
tx2_txid = self.nodes[0].sendrawtransaction(tx2_hex, True)
except JSONRPCException as exp:
assert_equal(exp.error['code'], -26)
else:
assert(False)
def test_too_many_replacements(self):
"""Replacements that evict too many transactions are rejected"""
# Try directly replacing more than MAX_REPLACEMENT_LIMIT
# transactions
# Start by creating a single transaction with many outputs
initial_nValue = 10*COIN
utxo = make_utxo(self.nodes[0], initial_nValue)
fee = 0.0001*COIN
split_value = int((initial_nValue-fee)/(MAX_REPLACEMENT_LIMIT+1))
actual_fee = initial_nValue - split_value*(MAX_REPLACEMENT_LIMIT+1)
outputs = []
for i in range(MAX_REPLACEMENT_LIMIT+1):
outputs.append(CTxOut(split_value, CScript([1])))
splitting_tx = CTransaction()
splitting_tx.vin = [CTxIn(utxo, nSequence=0)]
splitting_tx.vout = outputs
splitting_tx_hex = txToHex(splitting_tx)
txid = self.nodes[0].sendrawtransaction(splitting_tx_hex, True)
txid = int(txid, 16)
# Now spend each of those outputs individually
for i in range(MAX_REPLACEMENT_LIMIT+1):
tx_i = CTransaction()
tx_i.vin = [CTxIn(COutPoint(txid, i), nSequence=0)]
tx_i.vout = [CTxOut(split_value-fee, CScript([b'a']))]
tx_i_hex = txToHex(tx_i)
self.nodes[0].sendrawtransaction(tx_i_hex, True)
# Now create doublespend of the whole lot; should fail.
# Need a big enough fee to cover all spending transactions and have
# a higher fee rate
double_spend_value = (split_value-100*fee)*(MAX_REPLACEMENT_LIMIT+1)
inputs = []
for i in range(MAX_REPLACEMENT_LIMIT+1):
inputs.append(CTxIn(COutPoint(txid, i), nSequence=0))
double_tx = CTransaction()
double_tx.vin = inputs
double_tx.vout = [CTxOut(double_spend_value, CScript([b'a']))]
double_tx_hex = txToHex(double_tx)
try:
self.nodes[0].sendrawtransaction(double_tx_hex, True)
except JSONRPCException as exp:
assert_equal(exp.error['code'], -26)
assert_equal("too many potential replacements" in exp.error['message'], True)
else:
assert(False)
# If we remove an input, it should pass
double_tx = CTransaction()
double_tx.vin = inputs[0:-1]
double_tx.vout = [CTxOut(double_spend_value, CScript([b'a']))]
double_tx_hex = txToHex(double_tx)
self.nodes[0].sendrawtransaction(double_tx_hex, True)
def test_opt_in(self):
""" Replacing should only work if orig tx opted in """
tx0_outpoint = make_utxo(self.nodes[0], 1.1*COIN)
# Create a non-opting in transaction
tx1a = CTransaction()
tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0xffffffff)]
tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))]
tx1a_hex = txToHex(tx1a)
tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
# Shouldn't be able to double-spend
tx1b = CTransaction()
tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
tx1b.vout = [CTxOut(0.9*COIN, CScript([b'b']))]
tx1b_hex = txToHex(tx1b)
try:
tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
except JSONRPCException as exp:
assert_equal(exp.error['code'], -26)
else:
print tx1b_txid
assert(False)
tx1_outpoint = make_utxo(self.nodes[0], 1.1*COIN)
# Create a different non-opting in transaction
tx2a = CTransaction()
tx2a.vin = [CTxIn(tx1_outpoint, nSequence=0xfffffffe)]
tx2a.vout = [CTxOut(1*COIN, CScript([b'a']))]
tx2a_hex = txToHex(tx2a)
tx2a_txid = self.nodes[0].sendrawtransaction(tx2a_hex, True)
# Still shouldn't be able to double-spend
tx2b = CTransaction()
tx2b.vin = [CTxIn(tx1_outpoint, nSequence=0)]
tx2b.vout = [CTxOut(0.9*COIN, CScript([b'b']))]
tx2b_hex = txToHex(tx2b)
try:
tx2b_txid = self.nodes[0].sendrawtransaction(tx2b_hex, True)
except JSONRPCException as exp:
assert_equal(exp.error['code'], -26)
else:
assert(False)
# Now create a new transaction that spends from tx1a and tx2a
# opt-in on one of the inputs
# Transaction should be replaceable on either input
tx1a_txid = int(tx1a_txid, 16)
tx2a_txid = int(tx2a_txid, 16)
tx3a = CTransaction()
tx3a.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0xffffffff),
CTxIn(COutPoint(tx2a_txid, 0), nSequence=0xfffffffd)]
tx3a.vout = [CTxOut(0.9*COIN, CScript([b'c'])), CTxOut(0.9*COIN, CScript([b'd']))]
tx3a_hex = txToHex(tx3a)
self.nodes[0].sendrawtransaction(tx3a_hex, True)
tx3b = CTransaction()
tx3b.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0)]
tx3b.vout = [CTxOut(0.5*COIN, CScript([b'e']))]
tx3b_hex = txToHex(tx3b)
tx3c = CTransaction()
tx3c.vin = [CTxIn(COutPoint(tx2a_txid, 0), nSequence=0)]
tx3c.vout = [CTxOut(0.5*COIN, CScript([b'f']))]
tx3c_hex = txToHex(tx3c)
self.nodes[0].sendrawtransaction(tx3b_hex, True)
# If tx3b was accepted, tx3c won't look like a replacement,
# but make sure it is accepted anyway
self.nodes[0].sendrawtransaction(tx3c_hex, True)
if __name__ == '__main__':
ReplaceByFeeTest().main()

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